A) 0.5 h
B) 1 h
C) 8 h
D) 4 h
E) 2 h
Correct Answer: A
Solution :
Remaining quantity\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] where \[{{N}_{0}}=\]initial quantity \[\frac{{{N}_{0}}}{16}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{n}}\Rightarrow n=4\] n = number of half-lives \[\frac{t}{{{T}_{1/2}}}=4\] \[\frac{2}{{{T}_{1/2}}}=4\] \[{{T}_{1/2}}=\frac{2}{4}\] \[{{T}_{1/2}}=0.5\,h\]
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