A) 6 g
B) 5 g
C) 4 g
D) 2 g
E) 1 g
Correct Answer: D
Solution :
\[T=n\times {{t}_{1/2}}\] \[\Rightarrow \] \[32=n\times 8\] \[\therefore \] \[n=4\] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \] \[125={{N}_{0}}{{\left( \frac{1}{2} \right)}^{4}}\] \[125={{N}_{0}}\times \frac{1}{16}\] \[N=125\times 16=2000\,mg=2g\]You need to login to perform this action.
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