A) 0.99 N/m
B) 0.09 N/m
C) 0.59 m
D) 59 N/m
E) None of these
Correct Answer: B
Solution :
\[T=\frac{F}{2l}\] \[=\frac{1.8\times {{10}^{-2}}}{2\times 10\times {{10}^{-2}}}\] \[=0.09\,N\text{/}m\]You need to login to perform this action.
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