A) 94.9 atm
B) 0.949 atm
C) 949 atm
D) 0.648 atm
E) 1.248 atm
Correct Answer: B
Solution :
\[{{p}_{{{H}_{2}}O}}={{X}_{{{H}_{2}}O}}{{p}_{total}}\] \[=0.0287\times 0.977\] \[=0.028\,atm\] \[{{p}_{total}}={{p}_{dry\,air}}+{{p}_{{{H}_{2}}O}}\] \[{{p}_{dry\,air}}={{p}_{total}}-{{p}_{{{H}_{2}}O}}\] \[=0.977-0.028=0.949\text{ }atm\]
You need to login to perform this action.
You will be redirected in
3 sec
