A) \[O_{2}^{2-}>O_{2}^{-}>{{O}_{2}}>O_{2}^{+}\]
B) \[{{O}_{2}}>O_{2}^{+}>O_{2}^{-}>O_{2}^{2-}\]
C) \[O_{2}^{+}>{{O}_{2}}>O_{2}^{2-}>O_{2}^{-}\]
D) \[O_{2}^{+}>{{O}_{2}}>O_{2}^{-}>O_{2}^{2-}\]
E) \[{{O}_{2}}>O_{2}^{-}>O_{2}^{2-}>O_{2}^{+}\]
Correct Answer: D
Solution :
MO configuration of \[{{O}_{2}}\] is \[{{O}_{2}}(8+8=16)=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\] \[\pi 2p_{x}^{2}\approx \pi 2_{y}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{}\] \[\therefore \]Bond order\[=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{10-6}{2}=2\] Similarly, bond order of oxygen molecule ion \[(O_{2}^{+})=2.5\] Bond order of superoxide ion \[(O_{2}^{-})=1.5\] Bond order of peroxide ion \[(O_{2}^{2-})=1\] Bond strength \[\propto \] Bond order Hence, the order of bond strength is as \[O_{2}^{+}>{{O}_{2}}>O_{2}^{-}>O_{2}^{2-}\]
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