A) 0.14 T
B) 1.4T
C) 12.5 T
D) 140 T
Correct Answer: C
Solution :
We know that, \[i=\frac{q}{t}\] or \[i=qv\] \[\therefore \] The magnetic field at the centre of the orbit \[B=\frac{{{\mu }_{0}}i}{2r}=\frac{{{\mu }_{0}}}{2r}qv\] \[=\frac{4\pi \times {{10}^{-7}}\times 1.6\times {{10}^{-19}}\times 6.6\times {{10}^{15}}}{2\times 0.53\times {{10}^{-10}}}\] \[=\frac{2\pi \times 1.6\times 6.6}{5.3}=12.5T\]You need to login to perform this action.
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