A) \[mv\]
B) \[\sqrt{2}\,mv\]
C) \[\frac{mv}{\sqrt{2}}\]
D) \[2\,mv\]
Correct Answer: B
Solution :
Change in momentum \[=\,2mv\,\sin \theta \] \[=\,2mv\,\sin \frac{\pi }{4}\] \[=\sqrt{2}\,mv\]You need to login to perform this action.
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