A) \[\begin{align} & C{{H}_{3}}-\underset{OH}{\mathop{\underset{\mathbf{|}}{\mathop{CH}}\,}}\,-\underset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\mathop{CH}}\,}}\,-C{{H}_{3}} \\ & \,\,\,\,\,\,\text{3-methyl-2-butanol} \\ \end{align}\]
B) \[\begin{align} & C{{H}_{3}}-C\equiv C-CH{{(C{{H}_{3}})}_{2}} \\ & \,\,\,\,\,\,\text{4-methyl-2-butanol} \\ \end{align}\]
C) \[\begin{align} & C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\mathop{C{{H}_{2}}}}\,}}\,-\underset{C{{H}_{2}}}{\mathop{\underset{||}{\mathop{C}}\,}}\,-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C{{H}_{2}}}}\,}}\, \\ & \text{2-ethyl-3-methyl-but-1-ene} \\ \end{align}\]
D) \[\begin{align} & C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-\underset{C{{H}_{2}}C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}C{{H}_{3}} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{3-methyl-4-ethylheptane} \\ \end{align}\]
Correct Answer: D
Solution :
\[\overset{7}{\mathop{C{{H}_{3}}}}\,-\overset{6}{\mathop{C{{H}_{2}}}}\,-\overset{5}{\mathop{C{{H}_{2}}}}\,-\overset{4}{\mathop{\underset{C{{H}_{2}}-C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{{}^{3}CH}}\,}}\,-\overset{2}{\mathop{C{{H}_{2}}}}\,-\overset{1}{\mathop{C{{H}_{3}}}}\,\] Correct IUPAC name is 4-ethyl-3-methyl heptane because substituents are written in alphabetical order.
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