A) \[5{}^\circ C\]
B) \[70{}^\circ C\]
C) \[-\,30{}^\circ C\]
D) \[-50{}^\circ C\]
Correct Answer: B
Solution :
The given condition can be shown as In steady state, the temperature gradient is constant \[\therefore \] \[\frac{({{\theta }_{A}}-{{\theta }_{C}})}{6}=\frac{({{\theta }_{A}}-{{\theta }_{B}})}{20}\] \[\Rightarrow \] \[(100-{{\theta }_{C}})=\frac{6}{20}(100-0)\] \[\Rightarrow \] \[(100-{{\theta }_{C}})=30\] or \[{{\theta }_{C}}=100-30=70{}^\circ C\]You need to login to perform this action.
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