A) 15\[\Omega \]
B) 3\[\Omega \]
C) 3\[\Omega \]
D) 6\[\Omega \]
Correct Answer: C
Solution :
Given; efficiency \[\eta =50%\] \[\therefore \] \[e=\frac{E}{2}\] and \[i=\frac{E-e}{2}\] \[\Rightarrow \] \[i=\frac{E-E/2}{R}=\frac{E}{2R}\] \[\therefore \] \[R=\frac{E}{2i}=\frac{60}{2\times 10}=3\,\Omega \]You need to login to perform this action.
You will be redirected in
3 sec