A) zero
B) \[R\]
C) \[\frac{R}{2}\]
D) \[\frac{R}{4}\]
Correct Answer: B
Solution :
For a series LR, AC circuit, \[\tan \phi =\frac{{{X}_{L}}}{R}\] \[\Rightarrow \] \[\tan \frac{\pi }{4}=\frac{{{X}_{L}}}{R}\] \[\Rightarrow \] \[1=\frac{{{X}_{L}}}{R}\]or \[{{X}_{L}}=R\]You need to login to perform this action.
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