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CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    If the phase difference between two points separated by 0.8 in wave of frequency 120 Hz, is 0.5\[\pi \]then the velocity of the wave is will be

    A)  768 Hz                 

    B)  695 Hz

    C)  710 Hz                 

    D)  384 Hz

    Correct Answer: D

    Solution :

                    Here, path difference \[\Delta \,x=0.8\,m\] Frequency n =120 Hz Phase difference is \[\phi =0.5\,\pi \] The phase difference is given by       \[\phi =\frac{2\pi }{\lambda }\times \Delta \,x\]       \[\phi =0.5\,\pi \] \[0.5\,\pi =\frac{2\pi }{\lambda }\times 0.8\]       \[\lambda =\frac{2\pi \times 0.8}{0.5\,\pi }=3.2\,m\] Hence, the wave velocity is given by \[v=n\lambda \] (where\[\lambda \]is the wavelength of wave) \[=120\times 2.3=384\,m\text{/}s\]


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