A) the reaction is very close to equilibrium
B) the raction is very far to equilibrium
C) the reaction is at equilibrium
D) both the\[{{H}_{2}}(g)\]and\[NO(g)\]concentration must increase significantly to reach equilibrium
Correct Answer: A
Solution :
\[{{Q}_{c}}=\frac{[{{N}_{2}}O]\,[{{H}_{2}}O]}{[{{H}_{2}}]\,{{[NO]}^{2}}}=\frac{5.4\times 8.7}{0.05\times 0.02}=46.98\times {{10}^{3}}\] \[<{{K}_{c}}(140\times {{10}^{3}})\]i.e. reaction is close to equiblibrimYou need to login to perform this action.
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