A) \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\]
B) \[{{H}_{3}}{{O}^{+}}\]
C) \[HC{{r}_{2}}O_{4}^{-}\]
D) \[CrO_{4}^{2-}\]
Correct Answer: D
Solution :
Due to very small value of \[{{K}_{{{a}_{2}}}},\]the second ionisation will be very less and in solution, oxalate ion \[{{(C{{r}_{2}}{{O}_{4}})}^{2-}}\] will be at lowest concentration.You need to login to perform this action.
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