A) \[{{A}_{2}}{{B}_{5}}\]
B) \[{{A}_{3}}{{B}_{7}}\]
C) \[{{A}_{3}}{{B}_{10}}\]
D) \[{{A}_{7}}{{B}_{24}}\]
Correct Answer: C
Solution :
A face of this solid would appear as Missing \[A=\frac{1}{8}\times 2=\frac{1}{4}\] A present\[=1-\frac{1}{4}=\frac{3}{4}\] Missing \[B=\frac{1}{2}\] B present\[=3-\frac{1}{2}=\frac{5}{2}\] formula\[{{A}_{\frac{3}{4}}}{{B}_{\frac{5}{2}}}={{A}_{3}}{{B}_{10}}\]You need to login to perform this action.
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