A) For lead +4, for tin +2
B) for lead +2 , for tin +4
C) For lead +2, for tin +2
D) For lead +4, for tin +4
Correct Answer: B
Solution :
Since \[{{\Delta }_{r}}G{}^\circ \]is negative for first reaction, therefore, +2 oxidation state of Pb is more stable. Further, since\[{{\Delta }_{r}}G{}^\circ \]is positive for second reaction, therefore, +4 oxidation state of Sn is more stable. Thus option is correct.You need to login to perform this action.
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