CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    If the critical angle for total internal reflection from a medium to vacuum is \[30{}^\circ ,\] then the velocity of light in the medium will be

    A)  \[3\times {{10}^{8}}m\text{/}s\]                             

    B)  \[2\times {{10}^{8}}m\text{/}s\]

    C)  \[1.5\times {{10}^{8}}m\text{/}s\]                         

    D)  \[6\times {{10}^{8}}m\text{/}s\]

    Correct Answer: C

    Solution :

                    Critical angle \[C=30{}^\circ \] \[\sin C=\frac{v}{C}\] \[\sin 30{}^\circ =\frac{v}{3\times {{10}^{8}}}\] \[v=\frac{1}{2}\times 3\times {{10}^{8}}\] \[=1.5\times {{10}^{8}}\,m\text{/}s\]


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