A) Rs. 13500
B) Rs. 12500
C) Rs. 11500
D) Rs. 10500
Correct Answer: A
Solution :
Required sum\[=\frac{D\times {{100}^{3}}}{{{R}^{2}}(R+300)}\] \[\Rightarrow \] \[P=\frac{184\times {{100}^{3}}}{{{\left( \frac{20}{3} \right)}^{2}}\left( \frac{20}{3}+300 \right)}\] \[=\frac{184\times 9\times 3\times 1000000}{92\times 4\times 1000}\] \[\therefore \] \[P=\text{Rs}\text{.}\,13500\]You need to login to perform this action.
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