A) 768 Hz
B) 695 Hz
C) 710 Hz
D) 384 Hz
Correct Answer: D
Solution :
Here, path difference \[\Delta \,x=0.8\,m\] Frequency n =120 Hz Phase difference is \[\phi =0.5\,\pi \] The phase difference is given by \[\phi =\frac{2\pi }{\lambda }\times \Delta \,x\] \[\phi =0.5\,\pi \] \[0.5\,\pi =\frac{2\pi }{\lambda }\times 0.8\] \[\lambda =\frac{2\pi \times 0.8}{0.5\,\pi }=3.2\,m\] Hence, the wave velocity is given by \[v=n\lambda \] (where\[\lambda \]is the wavelength of wave) \[=120\times 2.3=384\,m\text{/}s\]You need to login to perform this action.
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