A) \[12\times {{10}^{3}}J\]
B) \[25\times {{10}^{-3}}J\]
C) \[0.48\times {{10}^{-3}}J\]
D) \[0.24\times {{10}^{-3}}J\]
Correct Answer: C
Solution :
Equation of SHM \[Y=3\,\sin \,(0.2t)\] Comparing with \[Y=a\,\,\sin \,\omega t,\]we have \[a=3\,m,\,\]\[\omega =0.2\,{{s}^{-1}}\] Mass of the particle \[=3g=3\times {{10}^{-3}}kg\] Therefore, kinetic energy of the particle is \[K=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{x}^{2}})\] \[=\frac{1}{2}\times 3\times {{10}^{-3}}\times {{(0.2)}^{2}}({{3}^{2}}-{{1}^{2}})\] \[\left( \because \,x=\frac{a}{3} \right)\] \[=0.48\times {{10}^{-3}}J\]You need to login to perform this action.
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