A) \[1.69\times {{10}^{37}}:1\]
B) \[1.243\times {{10}^{22}}:1\]
C) \[1:1679\times {{10}^{37}}\]
D) \[1:1.24243\times {{10}^{22}}\]
Correct Answer: A
Solution :
The reaction is \[Zn+CuS{{O}_{4}}\xrightarrow{{}}Cu+ZnS{{O}_{4}}\] \[Zn+C{{u}^{2+}}\xrightarrow{{}}Cu+Z{{n}^{2+}}\] \[{{E}_{cell}}=E{{{}^\circ }_{cell}}-\frac{0.0591}{2}\,\log \,\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] At equilibrium, \[{{E}_{cell}}=0\] \[E{{{}^\circ }_{cell}}=\frac{0.0591}{2}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] \[\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}=\frac{2\times E{{{}^\circ }_{cell}}}{0.0591}\] \[(E{{{}^\circ }_{cell}}=0.76+0.034=1.10\,V)\] \[=2\times 1.10/0.0591=37.225\] \[\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}=1.679\times {{10}^{37}}:1\]You need to login to perform this action.
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