A) 2500 K
B) 250 K
C) \[250{}^\circ C\]
D) \[25{}^\circ C\]
Correct Answer: C
Solution :
\[\frac{dp}{p}=\frac{dT}{T}\] \[dT=1{}^\circ C\] dP is change in pressure = 0.4 \[\frac{dp}{p}=\frac{0.4}{100}\] \[=\frac{0.4}{100}=\frac{1}{T}\] \[T=\frac{100}{0.4}=250{}^\circ C\]You need to login to perform this action.
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