A) total acceleration is zero
B) transverse acceleration is zero
C) longitudinal acceleration is zero
D) radial acceleration is zero
Correct Answer: C
Solution :
\[\frac{dL}{dt}=0\] \[\frac{d}{dt}(I\omega )=0\] \[\frac{I\,d\omega }{dt}=0\] \[I\,\alpha =0\] where, \[\alpha =\frac{d\omega }{dt}=\] longitudinal acceleration \[\alpha =0\] Hence, longitudinal acceleration of a planet is zero.You need to login to perform this action.
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