A) 34.2 g
B) 72 g
C) 342 g
D) 460 g
Correct Answer: B
Solution :
Boiling point \[({{T}_{b}})=100+\Delta {{T}_{b}}=100+{{k}_{b}}m\] Freezing point \[({{T}_{f}})=0-\Delta {{T}_{f}}=-{{k}_{f}}m\] \[{{T}_{b}}-{{T}_{f}}=(100+{{k}_{b}}m)-(-{{k}_{f}}m)\] \[105=100+0.51\,m+1.86\,m\] \[2.37\,m=5\] or \[m=\frac{5}{2.37}\] \[=2.11\] \[\therefore \]Weight of sucrose to be dissolved in 100g water \[=\frac{2.11\times 342}{1000}\times 100\] \[=72\,g\]You need to login to perform this action.
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