A) 0.36
B) 0.16
C) 0.24
D) 0.48
Correct Answer: D
Solution :
Hardy-Weinberg equilibrium states that these is a balance in the relative number of alleles. That is maintained within a large population over a period of time \[{{p}^{2}}+2pq+{{q}^{2}}=1\] \[p=0.6\] and \[q=0.4\] (given) \[\therefore \] 2\[pq\](frequency of heterozygote) \[=2\times 0.6\times 0.4=0.48\]You need to login to perform this action.
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