A) 481.5
B) 390.5
C) 299.5
D) 516.9
Correct Answer: B
Solution :
Sum of molar conductivity of reactants = sum of molar conductivity of produces Therefore, for the reaction \[C{{H}_{3}}COOH+NaCl\xrightarrow{{}}C{{H}_{3}}COONa+HCl\] \[\Lambda _{m}^{0}C{{H}_{3}}COOH=\Lambda _{m}^{0}C{{H}_{3}}COONa\]\[+\Lambda _{m}^{0}HCl-\Lambda _{m}^{0}NaCl\] \[=91+425.9-126.4\] \[=390.5\,\,{{\Omega }^{-1}}c{{m}^{2}}\,mo{{l}^{-1}}\]You need to login to perform this action.
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