A) 4
B) 1
C) 1/16
D) 16
Correct Answer: D
Solution :
\[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{2\,{{q}_{1}}2{{q}_{2}}}{{{(r/2)}^{2}}}=\left( \frac{4}{1/4} \right)F\] \[nF=16F,\]\[n=16\]You need to login to perform this action.
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