A) 66.6%
B) 96.7%
C) 6.67%
D) 33.3%
Correct Answer: A
Solution :
Let the per cent abundance of lighter isotope is \[\therefore \]Atomic mass,\[z=\frac{x(z-1)+(100-x)\,(z+2)}{x+100-x}\] \[3x=200\]or\[x=66.6%\]You need to login to perform this action.
You will be redirected in
3 sec