The output Y, when all the three inputs a first high and then low, will respectively bf
A) 1, 0
B) 1, 1
C) 0, 0
D) 0, 1
E) 1, -1
Correct Answer:
D
Solution :
Let inputs A, B and C are given to circuits As gate-I is AND and Gate-II is NAND Output \[Y=\overline{A.\,B.\,C}\] when \[A=1,\]\[B=1\]and \[C=1,\] \[Y=\overline{(1.1).\,\,1}=\bar{1}=0\] when \[A=0,\]\[B=0\]and \[C=0,\]then \[Y=\overline{(0\,.\,0)\,.\,\,0}=\bar{0}=1\]