A) \[{{[Ni\,{{(CN)}_{4}}]}^{2-}}\]
B) \[{{[Pd\,{{(CN)}_{4}}]}^{2-}}\]
C) \[{{[NiC{{l}_{4}}]}^{2-}}\]
D) \[{{[PdC{{l}_{4}}]}^{2-}}\]
E) None of these
Correct Answer: C
Solution :
\[{{[NiC{{l}_{4}}]}^{2-}}\] \[N{{i}^{2+}}={{d}^{8}}\] In \[NiC{{l}_{4}},\] pairing will not occur because \[C{{l}^{-}}\] is not a strong ligand. Therefore, it shows\[(s{{p}^{3}})\]tetrahedral geometry.You need to login to perform this action.
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