A) 9
B) 6
C) 10
D) 7
E) 4
Correct Answer: C
Solution :
Since, buffer is of base, therefore formula used is \[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] \[=5+\log \frac{0.01}{0.1}=5+\log {{10}^{-1}}\] \[=5-1=4\] \[pH=14-4=10\]You need to login to perform this action.
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