A) \[\frac{x}{m}=\frac{k}{c}\]
B) \[\frac{x}{m}=k{{c}^{2}}\]
C) \[\log \frac{x}{m}=\log k+\frac{1}{n}\log C\]
D) \[\log \frac{x}{m}=\frac{1}{n}\log k+\log C\]
E) \[\frac{1}{n}\log \frac{x}{m}=\log k+\frac{1}{n}\log C\]
Correct Answer: C
Solution :
The expression is \[\log \frac{x}{m}=\log k+\frac{1}{x}\log C\] \[\Rightarrow \] \[\frac{x}{m}=k{{C}^{1/n}}\] Taking log on both sides, we get \[\log \frac{x}{m}=\log k+\frac{1}{x}\log C\]You need to login to perform this action.
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