A) \[2H(H-h)\]
B) \[\sqrt{h\,(H-h)}\]
C) \[\sqrt{h\,(H+h)}\]
D) \[12\sqrt{h\,(H-h)}\]
E) \[\frac{2H}{h}\]
Correct Answer: D
Solution :
Let v be the velocity at point P of water while ejected, then \[\frac{1}{2}\rho {{v}^{2}}=\rho gh\] \[v=\sqrt{2gh}\] If emerging water will strike the floor after time t, then \[H-h=\frac{1}{2}g{{t}^{2}}\] \[\Rightarrow \] \[t=\sqrt{\frac{2\,(H-h)}{g}}\] The distance covered, d = vt \[\Rightarrow \] \[d=2\,\sqrt{h\,(H-h)}\]You need to login to perform this action.
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