A) 589
B) 586
C) 585
D) 590
E) 583
Correct Answer: E
Solution :
The source is moving with respect to wind at a speed of 36 km/h, i.e. 10 m/s, As the source is going away from observer who is at rest with respect to the medium, the frequency heard by the boy is\[v=\frac{v}{v+{{u}_{s}}}v=\frac{340}{340+10}\times 600\,Hz\] \[=583\,Hz\]You need to login to perform this action.
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