A) 2.4 eV
B) -8.4 eV
C) -7.2 eV
D) 13.2 eV
E) -3.4 eV
Correct Answer: E
Solution :
The energy of state is given as \[E=-\frac{13.6\,{{z}^{2}}}{{{n}^{2}}}=\frac{-13.6}{{{4}^{2}}}\times {{2}^{2}}\] \[=\frac{-13.6\times 4}{16}=-3.4\,eV\]You need to login to perform this action.
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