Solved papers for JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)
done JEE Main Online Paper (Held On 23 April 2013) Total Questions - 1
question_answer1) If\[\operatorname{S}={{\tan }^{-1}}\left( \frac{1}{{{\operatorname{n}}^{2}}+\operatorname{n}+1} \right)+\] \[{{\tan }^{-1}}\left( \frac{1}{{{\operatorname{n}}^{2}}+3\operatorname{n}+3} \right)+.......\] \[+{{\tan }^{-1}}\left( \frac{1}{1+(\operatorname{n}+19)(\operatorname{n}+20)} \right),\]then tan S is equal to :
JEE Main Online Paper ( Held On 23 April 2013 )