Solved papers for JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)
done JEE Main Online Paper (Held On 23 April 2013) Total Questions - 1
question_answer1) In the Bohr?s model of hydrogen- like atom the force between the nucleus and the electron is modified as \[\operatorname{F}=\frac{{{e}^{2}}}{4\pi {{\in }_{0}}}\left( \frac{1}{{{\operatorname{r}}^{2}}}+\frac{\beta }{{{\operatorname{r}}^{3}}} \right),\] Where \[\beta \]is a constant. For this atom, the radius of the \[{{\operatorname{n}}^{\operatorname{th}}}\] orbit in terms of the Bohr radius \[\left( {{a}_{0}}\frac{{{\in }_{0}}{{\operatorname{h}}^{2}}}{\operatorname{m}\pi {{e}^{2}}} \right)\] is
[JEE Main Online Paper ( Held On 23 April 2013 )