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DUMET Medical DUMET Medical Solved Paper-2001

  • question_answer
    A train weighing \[{{10}^{7}}N\] is running on a level track with uniform velocity of 36 km/h. The frictional force is \[0.5\times {{10}^{3}}N\]. What is the power of the engine? \[(g=10\,m/{{s}^{2}})\]

    A)  50 kW        

    B)  500 kW

    C)  0.5 kW        

    D)  5kW

    Correct Answer: D

    Solution :

    The rate of work done by engine is called power. Power \[=\frac{work}{time}\]= force \[=\frac{displacement}{time}=Fv\] Frictional force \[F=0.5\times {{10}^{3}}N\] Given, \[v=36\,km/h=\frac{36\times 5}{18}=10\,m/s\] \[\therefore \] \[P=Fv={{10}^{3}}\times 0.5\times 10\,W\] = 5 kW.


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