A) 3.3eV
B) 1.1eV
C) 2.2eV
D) none of there
Correct Answer: C
Solution :
From Einsteins photoelectric equation \[{{E}_{K}}=hv-W\] where W is work function of metal, \[{{E}_{K}}\]is maximum kinetic energy of electron and hv is energy of incident photon . Given, \[hv=3\,eV,\,\,W=0.8\,eV\] \[\therefore \] \[{{E}_{K}}=3-0.8=2.2\,eV\] \[\Rightarrow \] \[{{V}_{s}}=\frac{2.2\times 1.6\times {{10}^{-19}}}{1.6\times {{10}^{-19}}}=2.2\,eV\].
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