A) \[1873\,\overset{o}{\mathop{A}}\,\]
B) \[1675\,\overset{o}{\mathop{A}}\,\]
C) \[2875\,\overset{o}{\mathop{A}}\,\]
D) none of these
Correct Answer: A
Solution :
The minimum energy required for the emission of photoelectron from a metal is called the work function of that metal, and the corresponding wavelength is called wavelength \[(\lambda )\]. \[W=hv=\frac{hv}{\lambda }\] where h is Plancks constant and, c is speed of light. Given, \[W=6.26\,eV=6.626\times 1.6\times {{10}^{-19}}J\] \[\therefore \,\,\,\lambda =\frac{6.62\times {{10}^{-34}}\times 3\times {{10}^{8}}}{6.626\times 1.6\times {{10}^{-19}}}=1.873\times {{10}^{7}}m\]
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