A) 2.5m
B) 0.5m
C) 7.5m
D) 10m
Correct Answer: D
Solution :
Key Idea: Kinetic energy of cylinder is utilized in doing work against frictional force. The kinetic energy of cylinder is given by \[K=\frac{1}{2}m{{v}^{2}}\] where m is mass and v is velocity. Given, \[m=10\,kg,\,v=10\,m/s\] \[\therefore \] \[K=\frac{1}{2}\times 10\times {{(10)}^{2}}=500J\] ... (i) Work done by cylinder in rolling on plane = force of friction \[\times \]distance \[=\mu mg\times s\] \[=0.5\times 10\times 10\times s=50\,s\] ... (ii) Equating Eqs. (i) and (ii), we get \[500=50\,s\] \[\Rightarrow \] \[s=\frac{500}{50}=10\,m\].You need to login to perform this action.
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