A) 50 kW
B) 500 kW
C) 0.5 kW
D) 5kW
Correct Answer: D
Solution :
The rate of work done by engine is called power. Power \[=\frac{work}{time}\]= force \[=\frac{displacement}{time}=Fv\] Frictional force \[F=0.5\times {{10}^{3}}N\] Given, \[v=36\,km/h=\frac{36\times 5}{18}=10\,m/s\] \[\therefore \] \[P=Fv={{10}^{3}}\times 0.5\times 10\,W\] = 5 kW.You need to login to perform this action.
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