A) \[C{{H}_{3}}N{{H}_{2}}\]
B) \[C{{H}_{3}}CN\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: A
Solution :
\[C{{H}_{3}}CON{{H}_{2}}+B{{r}_{2}}+4NaOH\xrightarrow{\Delta }\underset{methyla\min e}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,\] \[+N{{a}_{2}}C{{O}_{3}}+2NaBr+2{{H}_{2}}O\] This is Hofmann bromamide reaction in which amide reacts with KOH and bromine to form amine having one carbon atom less than parent amide.You need to login to perform this action.
You will be redirected in
3 sec