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DUMET Medical DUMET Medical Solved Paper-2001

  • question_answer
    A cylinder of mass 10 kg is rolling on a plane with an initial velocity of 10 m/s. If the coefficient of friction between the surface and the cylinder is 0.5, then before stopping it will cover a distance of; \[(g=10\,m/{{s}^{2}})\]

    A)  2.5m          

    B)  0.5m

    C)  7.5m          

    D)  10m

    Correct Answer: D

    Solution :

    Key Idea: Kinetic energy of cylinder is utilized in doing work against frictional force. The kinetic energy of cylinder is given by \[K=\frac{1}{2}m{{v}^{2}}\] where m is mass and v is velocity. Given, \[m=10\,kg,\,v=10\,m/s\] \[\therefore \] \[K=\frac{1}{2}\times 10\times {{(10)}^{2}}=500J\] ... (i) Work done by cylinder in rolling on plane = force of friction \[\times \]distance \[=\mu mg\times s\] \[=0.5\times 10\times 10\times s=50\,s\] ... (ii) Equating Eqs. (i) and (ii), we get \[500=50\,s\] \[\Rightarrow \] \[s=\frac{500}{50}=10\,m\].


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