A) \[1.1\times {{10}^{-24}}kg\,m{{s}^{-1}}\]
B) \[1.1\times {{10}^{-34}}kg\,m{{s}^{-1}}\]
C) \[39.6\times {{10}^{-34}}kg\,m{{s}^{-1}}\]
D) \[39.6\times {{10}^{-24}}kg\,m{{s}^{-1}}\]
Correct Answer: A
Solution :
Key Idea: Use de-Broglies equation to find the momentum of the particle. \[\lambda =\frac{h}{mv}\] where \[\lambda =\] wavelength \[=6\,\overset{o}{\mathop{A}}\,=6\times {{10}^{-10}}m\] h = Plancks constant mv = momentum Momentum (mv) = \[\frac{h}{\lambda }\] \[=\frac{6.62\times {{10}^{-34}}}{6\times {{10}^{-10}}}\] \[=1.1\times {{10}^{-24}}kgm{{s}^{-1}}\]
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