A) \[C{{l}^{7+}}>S{{i}^{4+}}>M{{g}^{2+}}>N{{a}^{+}}\]
B) \[N{{a}^{+}}>M{{g}^{2+}}>S{{i}^{4+}}>C{{l}^{7+}}\]
C) \[N{{a}^{+}}>M{{g}^{2+}}>C{{l}^{7+}}>S{{i}^{4+}}\]
D) \[C{{l}^{7+}}>N{{a}^{+}}>M{{g}^{2+}}>S{{i}^{4+}}\]
Correct Answer: B
Solution :
Key Idea: Among isoelectronic species, greater the nuclear charge, smaller will be size. \[N{{a}^{+}}\] \[M{{g}^{2+}}\] \[S{{i}^{4+}}\] \[C{{l}^{7+}}\] No. of electrons 10 10 10 10 No. charge 11 12 14 17 \[\therefore \] The correct order of size is \[N{{a}^{+}}>M{{g}^{2+}}>S{{i}^{4+}}>C{{l}^{7+}}\]
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