A) \[C{{H}_{2}}O\]
B) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
C) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
D) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
Correct Answer: B
Solution :
Key Idea: Use the following formula to find the molecular formula of compound. (i) Molecular mass \[=2\times \] vapour density (ii) \[n=\] molecular mass / empirical formula mass (iii) Molecular formula \[=n\times \] empirical formula Given: Vapour density of \[C{{H}_{2}}O=30\] \[=2\times 30\] = 60 Empirical formula weight of \[C{{H}_{2}}O=12+1\times 2+16\] = 30 \[n=\frac{molecular\,\,weight}{empirical\,\,formula\,\,weight}\] \[=\frac{60}{30}\] = 2 \[\therefore \] Molecular formula \[=n\times \] empirical formula \[=2\,(C{{H}_{2}}O)\] \[={{C}_{2}}{{H}_{4}}{{O}_{2}}\]
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