A) \[C{{H}_{3}}N{{H}_{2}}\]
B) \[C{{H}_{3}}CN\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: A
Solution :
\[C{{H}_{3}}CON{{H}_{2}}+B{{r}_{2}}+4NaOH\xrightarrow{\Delta }\underset{methyla\min e}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,\] \[+N{{a}_{2}}C{{O}_{3}}+2NaBr+2{{H}_{2}}O\] This is Hofmann bromamide reaction in which amide reacts with KOH and bromine to form amine having one carbon atom less than parent amide.
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