A) \[C{{O}_{2}}\]
B) \[S{{O}_{3}}\]
C) \[{{C}_{2}}{{H}_{2}}\]
D) \[MgC{{l}_{2}}\]
Correct Answer: B
Solution :
Key Idea: Hybridisation and shape of molecule is decided by following formula. \[H=\frac{1}{2}(V+X-C+A)\] where H = hybridisation V = number of electrons in valance shall of central atom X = number of monovalent atoms C = charge on cation A = charge on anion \[C{{O}_{2}}\] \[H=\frac{1}{2}(4+0-0+0)\] = 2 \[\therefore \] sp hybridisation so shape is linear. \[S{{O}_{2}}\] \[H=\frac{1}{2}(6+0-0+0)\] = 3 \[\therefore \] \[s{{p}^{2}}\] hybridisation so shape is trigonal planar. \[{{C}_{2}}{{H}_{2}}\] Each carbon is sp hybridised and linear in shape. \[MgC{{l}_{2}}\] \[H=\frac{1}{2}(2+2-0+0)\] \[\therefore \] sp hybridisation and linear is the shape.
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