A) 4
B) 6
C) 3
D) 8
Correct Answer: A
Solution :
Key Idea: In fee, atoms are present at the eight corners of cube and at the centre of each face. \[\therefore \] Number of atoms present in fee crystal = \[\left( \begin{align} & No.\text{ }of\text{ }atoms\text{ }at \\ & corners \\ & + \\ & Contribution \\ & of\text{ }each\text{ }atom \\ \end{align} \right)+\left( \begin{align} & No.\text{ }of\text{ }atoms \\ & present\text{ }at\text{ }faces \\ & + \\ & Contribution\text{ }by \\ & each\text{ }atom \\ \end{align} \right)\] \[\therefore \] \[=\left( 8\times \frac{1}{8} \right)+\left( 6\times \frac{1}{2} \right)\] = 1 + 3 = 4
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